A) \[\frac{2\pi rn}{q}\times {{10}^{-7}}\]
B) \[\left( \frac{2\pi q}{r} \right)\times {{10}^{-7}}\]
C) \[\left( \frac{2\pi q}{nr} \right)\times {{10}^{-7}}\]
D) \[\left( \frac{2\pi nq}{r} \right)\times {{10}^{-7}}\]
Correct Answer: D
Solution :
\[{{\beta }_{centre}}=\frac{{{\mu }_{0}}I}{2r}\]\[=\frac{{{10}^{-7}}\times 4\pi \times (nq)}{2r}=\frac{2\pi nq}{r}\times {{10}^{-7}}\]
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