A) \[1.56\times {{10}^{-14}}J\]
B) \[5.5\times {{10}^{-14}}J\]
C) \[2.56\times {{10}^{-14}}J\]
D) \[4.56\times {{10}^{-14}}J\]
Correct Answer: C
Solution :
Electrostatic potential energy\[U=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}_{1}}{{q}_{2}}}{r}\] Here, \[{{q}_{1}}={{q}_{2}}=1.6\times {{10}^{-19}}C\] and \[r=9\times {{10}^{-15}}m\] \[\therefore \]\[U=\frac{9\times {{10}^{9}}\times 1.6\times {{10}^{-19}}\times 1.6\times {{10}^{-19}}}{9\times {{10}^{-15}}}\] \[=2.56\times {{10}^{-14}}J\]
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