J & K CET Medical J & K - CET Medical Solved Paper-2009

  • question_answer
    Energy stored per unit volume of a parallel plate capacitor having plate area A and plate separation d when charged to a potential of V volts is (air space in between the plates)

    A)  \[\frac{1}{2}{{C}^{2}}{{V}^{2}}\]                              

    B) \[\frac{{{q}^{2}}}{4C}\]

    C) \[\frac{1}{2}{{\varepsilon }_{0}}\left( \frac{v}{d} \right)\]                             

    D) \[\frac{1}{2}{{\varepsilon }_{0}}\left( \frac{{{v}^{2}}}{{{d}^{2}}} \right)\]

    Correct Answer: D

    Solution :

                     Energy density between the plates of a parallel plate capacitor. \[Energy\text{ }density=\frac{energy}{volume}=\frac{1}{2}{{\varepsilon }_{0}}{{E}^{2}}=\frac{1}{2}{{\varepsilon }_{0}}\frac{{{V}^{2}}}{{{d}^{2}}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner