A) 2
B) 5.5
C) 4
D) 1.5
Correct Answer: C
Solution :
Potential energy of the system \[\frac{-kqQ}{x}-\frac{kQq}{x}+\frac{k{{q}^{2}}}{2x}=0\] \[\Rightarrow \] \[\frac{-4kqQ+k{{q}^{2}}}{2x}=0\] \[\Rightarrow \] \[k{{q}^{2}}=4\,kQq\] \[\frac{q}{Q}=4\]You need to login to perform this action.
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