J & K CET Medical J & K - CET Medical Solved Paper-2009

  • question_answer
    The magnitude of electric field E required to balance an oil drop of mass m, carrying charge q is (g = acceleration due to gravity)

    A) \[\frac{q}{m}\] 

    B) \[\frac{mg}{{{q}^{2}}}\]

    C)  mgq                                     

    D) \[\frac{mg}{q}\]

    Correct Answer: D

    Solution :

                     To balance the oil drop the electric force should be equal to the weight of the oil drop. ie,          \[qE=mg\] or            \[E=\frac{mg}{q}\]


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