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J & K CET Medical J & K - CET Medical Solved Paper-2009

  • question_answer
    Two monoatomic ideal gases A and B occupying the same volume V, are at the same temperature T and pressure p. If they are mixed, the resultant mixture has volume V and temperature T. The pressure of the mixture is

    A)  p                                           

    B)  \[\frac{p}{2}\]

    C)  4p                                         

    D)  2p

    Correct Answer: D

    Solution :

                     \[\frac{{{p}_{1}}{{V}_{1}}}{{{T}_{1}}}=\frac{{{p}_{mix}}\times {{V}_{mix}}}{{{T}_{mix}}}\] Here,      \[{{T}_{1}}={{T}_{mix}}=T\]                 \[{{V}_{1}}=V+V\]                 \[{{V}_{mix}}=V\] \[\therefore \]  \[\frac{p\times 2V}{T}=\frac{{{p}_{mix}}\times V}{T}\] \[\Rightarrow \]               \[{{p}_{mix}}=2p\]         


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