J & K CET Medical J & K - CET Medical Solved Paper-2009

  • question_answer
    Two small spheres of radii r and 4r fall through a viscous liquid with the same terminal velocity. The ratio between the viscous forces acting on them is

    A)  1 : 2                                      

    B)  4 : 1

    C)  1:16                                      

    D)  1 : 4

    Correct Answer: D

    Solution :

                     The magnitude of the viscous force depends on the shape and size of the body, its speed and the viscosity of the fluid. Stokes established that if a sphere of radius r moves with velocity v through a fluid of viscosity\[\eta \], the viscous force opposing the motion of the sphere \[F=6\pi \eta rv\]\[\frac{{{F}_{1}}}{{{F}_{2}}}=\frac{{{r}_{1}}}{{{r}_{2}}}\]      [As \[\eta =\]constant and\[{{v}_{1}}={{v}_{2}}\]]           \[\frac{{{F}_{1}}}{{{F}_{2}}}=\frac{r}{4r}\]


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