A) \[\frac{3R}{10}\]
B) \[\frac{9R}{7}\]
C) \[\frac{8R}{5}\]
D) \[\frac{9R}{5}\]
Correct Answer: B
Solution :
If body is projected with velocity\[v(v<{{v}_{e}}),\]then height upto which it will rise, \[h=\frac{R}{\frac{v_{e}^{2}}{{{v}^{2}}}-1}\] \[v=\frac{3}{4}{{v}_{e}}\] (given) \[\therefore \] \[h=\frac{R}{\frac{v_{e}^{2}}{\frac{9}{16}v_{e}^{2}}-1}=\frac{9}{7}R\]
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