A) directly proportional to the length of the polanmeter tube only
B) directly proportional to the molar concentration of the compound
C) independent of the length of the polanmeter tube and concentration of the compound
D) directly proportional to both the length of the polarimeter tube and the molar concentration of the compound
Correct Answer: D
Solution :
\[\alpha =\frac{observed\text{ }rotation}{length(dm)\times concentration}\] \[\therefore \] observed rotation \[=a\times I\times c\] Thus, optical rotation of an optically active compound is directly proportion to both length of the polarimeter and molar concentration.
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