A) \[_{25}Mn\]
B) \[_{24}Cr\]
C) \[_{96}Cm\]
D) \[_{26}Fe\]
Correct Answer: C
Solution :
The electronic configuration of the given elements is as \[_{25}Mn=[Ar]\text{ }3{{d}^{5}},\text{ }4{{s}^{2}}\](Five unpaired electrons) \[_{24}Cr=[Ar]3{{d}^{5}},4{{s}^{1}}\] (Six unpaired electrons) \[_{96}Cm=[Rn]\text{ }5{{f}^{7}},\text{ }6{{d}^{1}},7{{s}^{2}}\](Eight unpaired electrons) \[_{26}Fe=[Ar]\text{ }3{{d}^{6}},\text{ }4{{s}^{2}}\](Four unpaired electrons) Thus,\[_{96}Cm\]has the highest number of unpaired electrons.
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