A) \[A{{B}_{6}}\]
B) \[A{{B}_{4}}\]
C) \[A{{B}_{8}}\]
D) \[{{A}_{5}}{{B}_{24}}\]
Correct Answer: B
Solution :
In the ccp structure, the A atoms are present at eight corners, so the number of A atoms per unit cell \[=8\times \frac{1}{8}\] = 1 atom But two A atoms are removed per unit cell So, the number of A atoms per unit cell \[=6\times \frac{1}{8}\] \[=\frac{3}{4}\] The number of B atoms per unit cell\[=6\times \frac{1}{2}\] \[=3\] \[\therefore \]The overall composition per unit cell\[={{A}_{\frac{3}{4}}}{{B}_{3}}\] or \[=A{{B}_{4}}\]
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