J & K CET Medical J & K - CET Medical Solved Paper-2009

  • question_answer
    The van der Waals constants for four gases P, Q, R and S are 4.17, 3.59, 6.71 and 3.8 atm\[{{L}^{2}}.mo{{l}^{-2}}\]. Therefore, the ascending order of their liquefaction is

    A) \[R<P<S<Q\]     

    B) \[Q<S<R<P\]

    C) \[Q<S<P<R\]     

    D) \[R<P<Q<S\]

    Correct Answer: C

    Solution :

                    As the value of van der Waals constant increases, ease of liquefaction of a gas also increases. The ascending order of van der Waals constants for gases P,Q, R, S is as \[\underset{(Q)}{\mathop{3.59}}\,<\underset{(S)}{\mathop{3.8}}\,<\underset{(P)}{\mathop{4.17}}\,<\underset{R}{\mathop{6.71}}\,\] Thus, the order of ease of liquification is \[Q<S<P<R\]


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