A) +2
B) +4
C) 0
D) + 3
Correct Answer: D
Solution :
The general electronic configuration of lanthanides is\[[Xe](n-2){{f}^{1-14}}(n-1){{d}^{1}}n{{s}^{2}}\] \[\because \]After the loss of both of the 65 electrons and also the solitary d electrons, the lanthanoids gain stable configurations. \[\therefore \]\[+\,III\text{ }(+3)\] oxidation state is most common among lanthanides.
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