J & K CET Medical J & K - CET Medical Solved Paper-2008

  • question_answer
    If the scalar and vector products of two vectors \[\vec{A}\] and \[\vec{B}\]are equal in magnitude, then the angle between the two vectors is

    A) \[45{}^\circ \]                                       

    B) \[90{}^\circ \]

    C) \[180{}^\circ \]              

    D) \[360{}^\circ \]

    Correct Answer: A

    Solution :

    According to problem, \[|(\overrightarrow{A}.\overrightarrow{B})|=|\overrightarrow{A}\times \overrightarrow{B}|\] or \[AB\text{ }cos\theta =AB\text{ }sin\theta \] or    \[tan\text{ }\theta =1\] (as\[AB\ne 0\]) or      \[\theta ={{45}^{o}}\]


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