J & K CET Medical J & K - CET Medical Solved Paper-2008

  • question_answer
    A body is under the action of two mutually perpendicular forces of 3 N and 4 N. The resultant force acting on the body is

    A)  7 N                                       

    B)  1 N

    C)  5 N                                       

    D)  zero

    Correct Answer: C

    Solution :

                     Resultant force, \[F=\sqrt{F_{1}^{2}+F_{2}^{2}+2{{F}_{1}}{{F}_{2}}\cos \theta }\] \[=\sqrt{{{(3)}^{2}}+{{(4)}^{2}}+2\times 3\times 4\cos {{90}^{o}}}\] \[=5N\]


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