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J & K CET Medical J & K - CET Medical Solved Paper-2008

  • question_answer
    A stress of \[3.18\times {{10}^{8}}N-{{m}^{-2}}\] is applied to a steel rod of length 1 m along its length. Its Youngs modulus is \[2\times {{10}^{11}}\text{ }N-{{m}^{-2}}.\] Then, the elongation produced in the rod (in mm) is

    A)  3.18                                      

    B)  6.36

    C)  5.18                                      

    D)  1.59

    Correct Answer: D

    Solution :

                     \[Y=\frac{Fl}{A\Delta l}\] \[\Rightarrow \]               \[\Delta l=\frac{Fl}{AY}\] \[\therefore \]  \[\Delta l=\frac{3.18\times {{10}^{8}}\times 1}{2\times {{10}^{11}}}\]                 \[=1.59\times {{10}^{-3}}m\] \[=1.59\text{ }mm\]


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