2. Solved Papers
  3. J & K CET Medical

J & K CET Medical J & K - CET Medical Solved Paper-2008

  • question_answer
    If g is the acceleration due to gravity on the surface of earth, its value at a height equal to double the radius of earth is

    A)  g                                            

    B)  \[\frac{g}{2}\]

    C)  \[\frac{g}{3}\]                                  

    D)  \[\frac{g}{9}\]

    Correct Answer: D

    Solution :

                     Acceleration due to gravity at a height h from the surface of the earth \[g=g\frac{1}{{{\left( 1+\frac{h}{R} \right)}^{2}}}\] Given,                   \[h=2R\] \[\therefore \]                  \[g=g\frac{1}{{{(1+2)}^{2}}}\] Or                           \[g=\frac{g}{9}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner