A) \[2\phi \]
B) \[\phi /2\]
C) \[\phi /4\]
D) \[\phi \]
Correct Answer: A
Solution :
By Gauss theorem \[{{\phi }_{E}}=\int{\overrightarrow{E}.d\overrightarrow{S}}=\frac{q}{{{\varepsilon }_{0}}}\] \[{{\phi }_{E}}\propto \int{dS}\] \[\therefore \]Flux will also doubled, ie,\[2\phi \].
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