A) \[2({{L}_{2}}+{{L}_{1}})\]
B) \[2({{L}_{2}}-{{L}_{1}})\]
C) \[2\left( {{L}_{2}}-\frac{{{L}_{1}}}{2} \right)\]
D) \[2\left( {{L}_{2}}+\frac{{{L}_{1}}}{2} \right)\]
Correct Answer: B
Solution :
If\[{{L}_{1}}\]and\[{{L}_{2}}\]are the first and second resonances, then we have \[{{L}_{1}}+e=\frac{\lambda }{4}\]and \[{{L}_{2}}+e=\frac{3\lambda }{4}\] \[\therefore \] \[{{L}_{2}}-{{L}_{1}}=\frac{\lambda }{2}\] \[\Rightarrow \] \[\lambda =2({{L}_{2}}-{{L}_{1}})\]
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