A) \[CO,\text{ }NO\]
B) \[{{N}_{3}}O,\text{ }CO\]
C) \[{{N}_{2}}O,C{{O}_{2}}\]
D) \[C{{O}_{2}},N{{O}_{2}}\]
Correct Answer: C
Solution :
Rate of diffusion depends upon the molecular masses of gases. Therefore, the gases which have equal molecular mass, have equal rates of diffusion. \[\frac{{{r}_{1}}}{{{r}_{2}}}=\sqrt{\frac{{{M}_{2}}}{{{M}_{1}}}}\] Molecular mass of \[{{N}_{2}}O=28+16=44\] Molecular mass of \[C{{O}_{2}}=12+32=44\] \[\therefore \] \[\frac{{{r}_{N{{O}_{2}}}}}{{{r}_{C{{O}_{2}}}}}=1\] \[\therefore \] \[{{r}_{N{{O}_{2}}}}={{r}_{C{{O}_{2}}}}\]
You need to login to perform this action.
You will be redirected in
3 sec
