A) \[L\text{ }at{{m}^{2}}\text{ }mo{{l}^{-1}}and\text{ }mol\text{ }{{L}^{-1}}\]
B) \[L\text{ }atm\text{ }mo{{l}^{2}}\text{ }and\text{ }mol\text{ }L\]
C) \[{{L}^{2}}\text{ }atm\text{ }mo{{l}^{-2}}\text{ }and\text{ }mo{{l}^{-1}}\text{ }L\]
D) \[{{L}^{-2}}at{{m}^{-1}}mo{{l}^{-1}}and\text{ }L\text{ }mo{{l}^{-2}}\]
Correct Answer: C
Solution :
van der Waals equation is \[\left( P+\frac{{{n}^{2}}a}{{{V}^{2}}} \right)(V-nb)=nRT\] \[\therefore \]Units of \[a=\frac{p{{V}^{2}}}{{{n}^{2}}}\] \[=\frac{atm\times {{L}^{2}}}{mo{{l}^{2}}}\] \[=\text{ }{{L}^{2}}atm\text{ }mo{{l}^{-2}}\] \[\therefore \] Units of \[b=\frac{V}{n}\] \[=\frac{L}{mol}=mo{{l}^{-1}}L\]
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