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J & K CET Medical J & K - CET Medical Solved Paper-2008

  • question_answer
    The oxidation state of sulphur in sodium tetrathionate\[(N{{a}_{2}}{{S}_{4}}{{O}_{6}})\]is

    A)  2                                            

    B)  0

    C)  2.5                                        

    D)  3.5

    Correct Answer: C

    Solution :

                    Let the oxidation state of sulphur in\[N{{a}_{2}}{{S}_{4}}{{O}_{6}}\]is\[x\]. \[N{{a}_{2}}{{S}_{4}}{{O}_{6}}\] \[1\times 2+4\times x+(-2)\times 6=0\] \[2+4x-12=0\] \[4x-10=0\] \[4x=10\] \[x=\frac{10}{4}=2.5\]


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