2. Solved Papers
  3. J & K CET Medical

J & K CET Medical J & K - CET Medical Solved Paper-2008

  • question_answer
    For a gas molecule with 6 degrees of freedom the law of equipartition of energy gives the following relation between the molecular specific heat \[({{C}_{v}})\] and gas constant (R)

    A)  \[{{C}_{v}}=\frac{R}{2}\]                                             

    B)  \[{{C}_{v}}=R\]

    C)  \[{{C}_{v}}=2R\]                                             

    D)  \[{{C}_{v}}=3R\]

    Correct Answer: D

    Solution :

                     From \[Cv=\frac{1}{2}fR\text{ }=\frac{1}{2}\times 6R=3R\]


You need to login to perform this action.
You will be redirected in 3 sec spinner