J & K CET Medical J & K - CET Medical Solved Paper-2007

  • question_answer
    In a spectrometer experiment the prisms A B, C with same angle but different refractive index \[{{\mu }_{A}}\]= 1.33, \[{{\mu }_{B}}\]= 1.5, \[{{\mu }_{C}}\]= 1.44 are used. The corresponding angles of minimum deviation \[{{D}_{A}},\text{ }{{D}_{B}},\text{ }{{D}_{C}}\]measured will be such that

    A) \[{{D}_{A}}>\text{ }{{D}_{B}}>\text{ }{{D}_{c}}\]                              

    B)  \[{{D}_{A}}<\text{ }{{D}_{B}}<\text{ }{{D}_{c}}\]

    C) \[{{D}_{A}}<\text{ }{{D}_{c}}<\text{ }{{D}_{B}}\]                              

    D)  \[{{D}_{A}}>\text{ }{{D}_{c}}>\text{ }{{D}_{B}}\]

    Correct Answer: C

    Solution :

                     Refractive index of the material of a prism is given by \[\mu =\frac{\sin (Q+{{\delta }_{m}})/2}{\sin \frac{A}{2}}\] Since, refractive angle is same for three prisms                 \[\mu \propto {{\delta }_{m}}\]ie,\[\mu \propto D\] \[\therefore \]  \[{{D}_{A}}<{{D}_{C}}<{{D}_{B}}\]


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