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J & K CET Medical J & K - CET Medical Solved Paper-2007

  • question_answer
    The time period of a freely suspended bar magnet in a field is 2 s. It is cut into two equal parts along its axis, then the time period is

    A)  4 s                                         

    B)  0.5 s

    C)  2 s                                         

    D)  0.25 s

    Correct Answer: C

    Solution :

                     \[T=2\pi \sqrt{\frac{I}{MB}}\] \[T=2s,I=\frac{I}{2},M=\frac{M}{2}\] \[\therefore \]  \[T=T\] \[\Rightarrow \]               \[T=2s\]              


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