A) 36 kg-wt
B) 27 kg-wt
C) 18 kg-wt
D) 72 kg-wt
Correct Answer: A
Solution :
Fundamental frequency, \[n=\frac{1}{2l}\sqrt{\frac{T}{m}}\] ie, \[n\propto \sqrt{T}\] \[\therefore \] \[\frac{{{n}_{1}}}{{{n}_{2}}}=\sqrt{\frac{{{T}_{1}}}{{{T}_{2}}}}\] \[\Rightarrow \] \[\frac{450}{900}=\sqrt{\frac{9}{{{T}_{2}}}}\] \[{{T}_{2}}=36\,kg-wt\]
You need to login to perform this action.
You will be redirected in
3 sec
