A) 3 : 1
B) 1 : 3
C) 1 : 9
D) 9 : 1
Correct Answer: B
Solution :
\[Intensity\propto {{(amplitude)}^{2}}\] \[\therefore \] \[\frac{{{I}_{1}}}{{{I}_{2}}}=\frac{a_{1}^{2}}{a_{2}^{2}}\] \[\frac{1}{9}=\frac{a_{1}^{2}}{a_{2}^{2}}\] \[\Rightarrow \] \[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{1}{3}\]
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