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  3. J & K CET Medical

J & K CET Medical J & K - CET Medical Solved Paper-2007

  • question_answer
    Work done in converting one gram of ice at \[-10{}^\circ C\] into steam at \[100{}^\circ C\] is

    A)  3045 J  

    B)  6056 J

    C)  721 J                                    

    D)  616 J

    Correct Answer: A

    Solution :

                     \[W=JQ\] \[=4.2(0.5\times 10+1\times 80+1\times 100+1\times 540)\] \[=3045J\]


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