A) increases by 20%
B) decreases by 20%
C) increases by 25%
D) decreases by 25%
Correct Answer: C
Solution :
According to Boyles law \[{{p}_{1}}{{V}_{1}}={{p}_{2}}{{V}_{2}}\] As the pressure is decreased by 20%, so \[{{p}_{2}}=\frac{80}{100}{{p}_{1}}\] \[{{p}_{1}}{{V}_{1}}=\frac{80}{100}{{p}_{1}}{{V}_{2}}\] \[{{V}_{1}}=\frac{80}{100}{{V}_{2}}\] \[\therefore \]\[{{V}_{2}}\]percentage increase in volume \[=\frac{{{V}_{2}}-{{V}_{1}}}{{{V}_{1}}}\times 100\] \[=\frac{100-80}{80}\times 100\] \[=25%\]
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