A) the baby is \[R{{h}^{+}}\] and mother \[R{{h}^{-}}\]
B) the baby is \[R{{h}^{+}}\]and mother \[R{{h}^{+}}\]
C) the baby is \[R{{h}^{-}}\]and mother \[R{{h}^{-}}\]
D) the baby is \[R{{h}^{-}}\]and mother \[R{{h}^{+}}\]
Correct Answer: A
Solution :
Individual incompatibility between mother and foetus sometimes results in a condition called hemolytic disease of the new born (HDN) or erythroblastosis foetalis and this occurs when the mother is Rh- and the foetus is Rh+. In first pregnancy, Rh+ blood from the foetus enters the circulation of an Rh- mother, antibodies against the Rh antigen will be made. Foetal blood most often enters the maternal circulation during child birth. So, the first Rh+ child is not affected, however, the maternal circulation now contains antibodies and memory cells against the Rh- antigen. During second pregnancy, a subsequent Rh+ foetus makes a secondary response from the maternal immune system resulting massive amount of antibodies. Rh- antibodies cross the placenta in late stages of pregnancy and destroys the RBCs of the foetus. The resulting anaemia can kill the foetus before birth.
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