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J & K CET Medical J & K - CET Medical Solved Paper-2007

  • question_answer
    The radius of the earth is R. The height of a point vertically above the earths surface at which acceleration due to gravity becomes 1% of its value at the surface is

    A)  8R                                         

    B)  9R         

    C)  10R                                       

    D)  20R

    Correct Answer: B

    Solution :

                     Acceleration due to gravity at a height h from earth?s surface \[g=\frac{GM}{{{(R+h)}^{2}}}\] Since,   \[g=\frac{1}{100}\]of g                 \[\frac{g}{100}=\frac{GM}{{{(R+h)}^{2}}}\]                 \[\frac{{{(R+h)}^{2}}}{100}=\frac{GM}{g}\]                 \[\frac{{{(R+h)}^{2}}}{100}={{R}^{2}}\]                   \[\left[ \because g=\frac{GM}{{{R}^{2}}} \right]\]                 \[R+h=10R\]                 \[h=9R\]


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