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J & K CET Medical J & K - CET Medical Solved Paper-2007

  • question_answer
    The molarity of the solution obtained by dissolving 2.5 g of\[NaCl\]in 100 mL of water is

    A)  0.00428 moles                 

    B)  428 moles

    C)  0.428 moles     

    D)  0.0428 moles

    Correct Answer: C

    Solution :

                    Molarity(M) \[=\frac{\frac{weight\text{ }of\text{ }solute}{molecular\text{ }weight\text{ }of\text{ }solute}}{volume\text{ }of\text{ }the\text{ }solution}\times 1000\] \[=\frac{2.5\times 1000}{58.5\times 100}\] \[=0.428\text{ }mol\]


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