A) \[mo{{l}^{-1}}{{L}^{-1}}{{s}^{-1}}\]
B) \[mo{{l}^{-1}}L\text{ }{{s}^{-1}}\]
C) \[mo{{l}^{-1}}\text{ }L\text{ }s\]
D) \[mol\text{ }{{L}^{-1}}{{s}^{-1}}\]
Correct Answer: B
Solution :
\[\frac{dx}{dt}=k{{[A]}^{2}}\] \[k=\frac{dx}{dt{{[A]}^{2}}}\] \[=\frac{mol{{(L)}^{2}}}{L\times s\times {{(mol)}^{2}}}\] \[=mo{{l}^{-1}}L\,{{s}^{-1}}\]
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