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J & K CET Medical J & K - CET Medical Solved Paper-2007

  • question_answer
    The half-life of\[R{{a}^{226}}\]is 1620 yr, the decay constant (k) is

    A)  0.000452            

    B)  0.0004278

    C)  0.04278               

    D)  0.004278

    Correct Answer: B

    Solution :

                     Decay constant\[(k)=\frac{0.693}{{{t}_{1/2}}}\] \[{{t}_{1/2}}=\frac{0.693}{k}\] \[=\frac{0.693}{1620}\] \[=0.0004278\]


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