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J & K CET Medical J & K - CET Medical Solved Paper-2006

  • question_answer
    A block of mass 2 kg rests on a horizontal surface. If a horizontal force of 5 N is applied on the block the frictional force on, it is: (\[{{\mu }_{k}}=0.4,{{\mu }_{s}}=0.5\])

    A)  5N                                        

    B)  10 N

    C)  8 N                                       

    D)  zero

    Correct Answer: C

    Solution :

                     The frictional force F is given by \[F={{\mu }_{k}}mg\] Given, \[{{u}_{k}}=0.4,m=2kg,g=10m/{{s}^{2}}\] \[\therefore \]  \[F=0.4\times 2\times 10\] \[F=8N\]


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