A) \[Cu(s)+ZnS{{O}_{4}}(aq)\to CuS{{O}_{4}}(aq)+Zn(s)\]
B) \[Zn(s)+CuS{{O}_{4}}(aq)\to Cu(s)+ZS{{O}_{4}}(aq)\]
C) \[Ni(s)+ZnS{{O}_{4}}(aq)\to NiS{{O}_{4}}(aq)+Zn(s)\]
D) \[2Na(s)+CdS{{O}_{4}}(aq)\to N{{a}_{2}}S{{O}_{4}}(aq)\] \[+Cd(s)\]
Correct Answer: B
Solution :
In galvanic cell (Daniel cell) the electrical energy is produced from chemical reactions. At anode: \[Zn\to Z{{n}^{2+}}+2{{e}^{-}}\] (oxidation) At cathode:\[\underline{Cu+2{{e}^{-}}\to Cu\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(reduction)}\] Cell reaction: \[Zn+C{{u}^{2+}}\to Z{{n}^{2+}}+Cu\] Or\[Zn(s)+CuS{{O}_{4}}(aq)\to Cu(s)+ZnS{{O}_{4}}(aq)\]
You need to login to perform this action.
You will be redirected in
3 sec
