A) all bands are uniformly bright
B) all bands are uniformly wide
C) central band is narrower
D) central band is wider
Correct Answer: D
Solution :
In the diffraction due to narrow slit, the first minimum on either side of the central maximum in the direction 9 is given by \[e\text{ }sin\text{ }\theta =\pm \lambda \] When slit is narrowed that is e is reduced, the angle\[\theta \]increases which means that the central maximum becomes wider.
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