question_answer

Two particles of equal mass arc connected to a rope AB of negligible mass, such that one is at end A and the other dividing the length of the rope in the ratio 1 : 2 from B. The rope is rotated about end B in a horizontal plane. Ratio of the tensions in the smallei part to the other is (ignore effect of gravity) :

A)  4:3                                        

B)  1 : 4

C)  1: 2                                       

D)  1 : 3

Correct Answer: D

Solution :

                 Lee\[x\]be distance from A to O, and L the total length of string. Then, ratio of moments is \[\frac{{{m}_{1}}}{{{m}_{2}}}=\frac{(L-x)}{L}=\frac{3-2}{3}=\frac{1}{3}\]