A) \[60{}^\circ \]
B) \[45{}^\circ \]
C) \[30{}^\circ \]
D) \[75{}^\circ \]
Correct Answer: A
Solution :
\[\tau =MB\text{ }sin\,\theta \] where \[\theta ={{90}^{o}}\] \[\therefore \] \[\tau =MB\] Given, \[{{\tau }_{2}}=\frac{1}{2}{{\tau }_{1}}\] \[\therefore \] \[MB\sin \theta =\frac{1}{2}\,MB\] \[\therefore \] \[\sin \theta =\frac{1}{2}\] \[\Rightarrow \] \[\theta ={{30}^{o}}\] Angle of rotation is\[={{90}^{o}}-{{30}^{o}}={{60}^{o}}\]
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