A) is ahead in phase by\[\pi \]
B) lags in phase by \[\pi \]
C) is ahead in phase by\[\frac{\pi }{2}\]
D) lags in phase by \[\frac{\pi }{2}\]
Correct Answer: D
Solution :
In a purely inductive circuit, current is
\[i={{i}_{0}}\sin \left( \omega t-\frac{\pi }{2} \right)\] Which shows that the current lags behind the emf by a phase angle of \[\frac{\pi }{2}\]or\[{{90}^{o}}\]or the emf leads the current by a phase angle of\[\frac{\pi }{2}\]or\[{{90}^{o}}\]
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