A) 0.1 V
B) 0.5 V
C) IV
D) 5 V
Correct Answer: D
Solution :
The magnetic flux through area A placed in magnetic field B is \[\phi =BA\,\cos \theta \] Given, \[\theta =0{}^\circ ,\text{ }B=1\text{ }T/s,\] \[A={{(10)}^{2}}c{{m}^{2}}={{10}^{-2}}{{m}^{2}}\] \[\therefore \] \[\phi =1\times {{10}^{-2}}\] By Faraday's law, induced emf is \[e=-N\frac{\Delta \phi }{\Delta t}\]
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