J & K CET Medical J & K - CET Medical Solved Paper-2006

  • question_answer
    Two identical spheres with charges 4q, - 2q kept some distance apart exert a force F on each other. If they are made to touch each other and replaced at their old positions, the force between them will be :

    A) \[\frac{1}{9}F\]                                

    B) \[\frac{1}{8}F\]

    C) \[\frac{9}{8}F\]                                

    D) \[\frac{8}{9}F\]

    Correct Answer: B

    Solution :

                     When spheres are touched and separated, charge is \[q'=\frac{4q-2q}{2}=\frac{2q}{2}=q\] From Coulomb's law                 \[F=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{(4q)(-2q)}{r}\]             ??? (i) When made to touch                 \[F'=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}^{2}}}{r}\]                            ?? (ii) From Eqs. (i) and (ii), we get                 \[F'=\frac{F}{8}\]


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