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J & K CET Medical J & K - CET Medical Solved Paper-2006

  • question_answer
    A disc of moment of inertia 5 kg-m is acted upon by a constant torque of 40 Nm. Starting from rest the time taken by it to acquire an angular velocity of 24 rad/s is:

    A)  3 s                                         

    B)  4 s

    C)  2.5 s                                     

    D)  120 s

    Correct Answer: A

    Solution :

                     Torque is defined as rate of change of angular momentum \[\therefore \]  \[\tau =\frac{dJ}{dt}=\frac{d(I\omega )}{dt}\] Given,\[\tau =40\text{ }Nm,\text{ }I=5\text{ }kg-{{m}^{2}},\text{ }\omega =24\text{ }rad/s\] \[dt=\frac{d(I\omega )}{\tau }=\frac{5\times 24}{40}=3s\]


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