J & K CET Medical J & K - CET Medical Solved Paper-2006

  • question_answer
    What is the two third life of a first order reaction having\[k=5.48\times {{10}^{-14}}{{s}^{-1}}\]:

    A) \[2.01\times {{10}^{11}}s\]                         

    B) \[2.01\times {{10}^{13}}s\]

    C)  \[8.08\times {{10}^{13}}s\]        

    D)  \[16.04\times {{10}^{11}}s\]

    Correct Answer: B

    Solution :

                    For two-third of a reaction: \[{{[A]}_{0}}=a,[A]=a-\frac{2}{3}a=\frac{a}{3}\] \[{{t}_{2/3}}=\frac{2.303}{k}\log \frac{{{[A]}_{0}}}{[A]}\] \[=\frac{2.303}{k}\log \frac{a}{\frac{a}{3}}=\frac{2.303}{k}\log \,3\] \[{{t}_{2/3}}=\frac{2.303\times 0.4771}{5.48\times {{10}^{-14}}}=2.01\times {{10}^{13}}s\]


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