A) KOH, alcohol\[/\Delta \]
B) KOH, water\[/\Delta \]
C) Zn, alcohol \[/\Delta \]
D) Na, alcohol\[/\Delta \]
Correct Answer: C
Solution :
1, 2 dihalogen (vicinal) derivatives of the alkanes on reaction with zinc dust and methanol produces alkenes by loss of two halogen atoms (dehalogenation). \[\underset{1,\text{ }2-dibromopropane}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\mathop{CH}}\,-\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\mathop{CH}}\,}}\,+Zn\xrightarrow[{}]{alcohol/\Delta }\]\[\underset{propylene}{\mathop{C{{H}_{3}}CH=C{{H}_{2}}}}\,\]
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