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J & K CET Medical J & K - CET Medical Solved Paper-2006

  • question_answer
    The ionic radii \[(\overset{\text{o}}{\mathop{\text{A}}}\,)\] of  \[{{C}^{4-}}\] and \[{{O}^{2-}}\] respectively are 2.60 and 1.40. The ionic radius of the isoelectronic ion \[{{N}^{3-}}\] would be:

    A)  2.6                                        

    B)  1.71

    C)  1.4                                        

    D)  0.95

    Correct Answer: B

    Solution :

                    \[{{C}^{4-}},{{N}^{3-}}\]and\[{{O}^{2-}}\]are isoelectronic species. The size of ionic radius of isoelectronic species decrease with increase the nuclear charge. Hence, the order of ionic radius is: Species:               \[{{C}^{4-}}~\,\,\,\,\,\,>\,\,\,\,\,\,~{{N}^{3-}}\,\,\,\,\,\,~>\,\,\,\,\,\,\,~{{O}^{2-}}\] lonic radii             \[2.60~~~~~~~~1.71~~~~~~~~~~~1.40\]


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