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J & K CET Medical J & K - CET Medical Solved Paper-2004

  • question_answer
    The equilibrium \[{{P}_{4}}(s)+6C{{l}_{2}}(g)4PC{{l}_{3}}(g)\]is attained by mixing equal moles of\[{{P}_{4}}\]and\[C{{l}_{2}}\]in an evacuated vessel. Then at equilibrium is:

    A)  \[[C{{l}_{2}}]>[PC{{l}_{3}}]\]     

    B)  \[[C{{l}_{2}}]>[{{P}_{4}}]\]

    C)  \[[{{P}_{4}}]>[C{{l}_{2}}]\]                         

    D)  \[[PC{{l}_{3}}]>[{{P}_{4}}]\]

    Correct Answer: C

    Solution :

                    For the reaction:
                      \[{{P}_{4}}(s)+6C{{l}_{2}}(g)4PC{{l}_{3}}(g)\]
    At \[t=0\] 1 1 0
    At eq. \[(1-x)\] \[(1-6x)\] \[4x\]
    As \[(1-x)>(1-6x)\]
    Hence, at equilibrium \[[{{P}_{4}}]>[C{{l}_{2}}]\]


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