J & K CET Medical J & K - CET Medical Solved Paper-2004

  • question_answer
    Vapour pressure of dilute aqueous solution of glucose is 750 mm of mercury at 373 K. The mole fraction of solute is:

    A)  \[\frac{1}{76}\]                               

    B)  \[\frac{1}{7.6}\]

    C)  \[\frac{1}{38}\]                               

    D)  \[\frac{1}{10}\]

    Correct Answer: A

    Solution :

                    According to Raoult's law: Mole fraction of solute \[=\frac{P-{{P}_{s}}}{P}\] \[=\frac{760-750}{760}=\frac{10}{760}=\frac{1}{76}\]


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