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J & K CET Medical J & K - CET Medical Solved Paper-2004

  • question_answer
    For the reaction,\[{{N}_{2}}+3{{H}_{2}}2N{{H}_{3}};\Delta H=?\]

    A)  \[\Delta E+2RT\]             

    B) \[\Delta E-2RT\]

    C)  \[\Delta E+RT\]                               

    D) \[\Delta E-RT\]

    Correct Answer: B

    Solution :

                    \[{{N}_{2}}+3{{H}_{2}}2N{{H}_{3}}\] \[\Delta H=\Delta E+\Delta nRT\] \[\Delta n=2-4=-2\] \[\therefore \]  \[\Delta H=\Delta E+(-2)RT\]                 \[\Delta H=\Delta E-2RT\]


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