A) 1
B) 0.8
C) 0.4
D) 0.6
Correct Answer: B
Solution :
Fringe visibility \[V=\frac{2\sqrt{{{I}_{1}}{{I}_{2}}}}{{{I}_{1}}+{{I}_{2}}}\] where\[{{I}_{1}}\]and\[{{I}_{2}}\]are intensities of coherent sources. Given, \[\frac{{{I}_{1}}}{{{I}_{2}}}=\frac{1}{4}\] \[\therefore \] \[{{I}_{2}}=4{{I}_{1}}\] \[\therefore \]Fringe visibility\[=\frac{2\sqrt{{{I}_{1}}\times 4{{I}_{1}}}}{({{I}_{1}}+4{{I}_{1}})}\] \[\Rightarrow \] \[V=0.8\]
You need to login to perform this action.
You will be redirected in
3 sec
